SQL每日一题F1028，关联子查询

create table F1028A (aid varchar(20), bid varchar(20) ) insert into F1028A values (‘跑步’,‘张三’); insert into F1028A values (‘游泳’,‘张三’); insert into F1028A values (‘跳远’,‘李四’); insert into F1028A values (‘跳高’,‘王五’);

create table F1028B (aid varchar(20), bid varchar(20), cid varchar(20) ) insert into F1028B values (‘跑步’,‘张三’,‘胜利’); insert into F1028B values (‘游泳’,‘张三’,‘胜利’); insert into F1028B values (‘跳高’,‘王五’,‘胜利’);

– Q：anum表示每个人参加的项目数，bnum表示每个人在各自项目中胜利的次数，该如何写这个查询？

–解法一： SELECT ISNULL(t1.bid, t2.bid) AS bid, ISNULL(t1.anum, 0) anum, ISNULL(t2.bnum, 0) bnum FROM ( SELECT bid, COUNT(1) AS anum FROM F1028A GROUP BY bid ) t1 FULL JOIN ( SELECT bid, SUM(CASE WHEN cid = ‘胜利’ THEN 1 ELSE 0 END ) bnum FROM F1028B GROUP BY bid ) t2 ON t2.bid = t1.bid;

–解法二： SELECT bid ,COUNT(1) AS anum ,ISNULL( ( SELECT SUM(CASE WHEN cid=‘胜利’ THEN 1 ELSE 0 END) FROM F1028B b WHERE a.bid=b.bid ),0) AS bnum FROM F1028A a GROUP BY bid